Y=-0.01x^2+0.3+2

Solution for Y=-0.01x^2+0.3+2 equation:

=-0.01Y^2+0.3+2

We move all terms to the left:

-(-0.01Y^2+0.3+2)=0

We get rid of parentheses

0.01Y^2-0.3-2=0

We add all the numbers together, and all the variables

0.01Y^2-2.3=0

a = 0.01; b = 0; c = -2.3;
Δ = b2-4ac
Δ = 02-4·0.01·(-2.3)
Δ = 0.092
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.092}}{2*0.01}=\frac{0-\sqrt{0.092}}{0.02}
=-\frac{\sqrt{}}{0.02}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.092}}{2*0.01}=\frac{0+\sqrt{0.092}}{0.02}
=\frac{\sqrt{}}{0.02}
$